Base | Representation |
---|---|

bin | 100101110101100000… |

… | …0001100001001011011 |

3 | 21202201121011200200111 |

4 | 1023223000030021123 |

5 | 2312401014404333 |

6 | 101154322345151 |

7 | 5604334340605 |

oct | 1135300141133 |

9 | 252647150614 |

10 | 81252106843 |

11 | 31505772526 |

12 | 138b71bb1b7 |

13 | 787b67163b |

14 | 3d0b190175 |

15 | 21a839d4cd |

hex | 12eb00c25b |

81252106843 has 2 divisors, whose sum is σ = 81252106844. Its totient is φ = 81252106842.

The previous prime is 81252106813. The next prime is 81252106853. The reversal of 81252106843 is 34860125218.

It is a strong prime.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2^{k}-81252106843 is a prime.

It is a junction number, because it is equal to *n*+sod(*n*) for *n* = 81252106796 and 81252106805.

It is not a weakly prime, because it can be changed into another prime (81252106813) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 40626053421 + 40626053422.

It is an arithmetic number, because the mean of its divisors is an integer number (40626053422).

Almost surely, 2^{81252106843} is an apocalyptic number.

81252106843 is a deficient number, since it is larger than the sum of its proper divisors (1).

81252106843 is an equidigital number, since it uses as much as digits as its factorization.

81252106843 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 92160, while the sum is 40.

The spelling of 81252106843 in words is "eighty-one billion, two hundred fifty-two million, one hundred six thousand, eight hundred forty-three".

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