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813441307249 is a prime number
BaseRepresentation
bin10111101011001001110…
…00010101001001110001
32212202122010022220012001
423311210320111021301
5101311411433312444
61421404554134001
7112524556012504
oct13654470251161
92782563286161
10813441307249
11293a8445888a
12111797a21301
135b9268c350c
142b52956913b
151625d3668d4
hexbd64e15271

813441307249 has 2 divisors, whose sum is σ = 813441307250. Its totient is φ = 813441307248.

The previous prime is 813441307213. The next prime is 813441307313. The reversal of 813441307249 is 942703144318.

813441307249 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 756717311025 + 56723996224 = 869895^2 + 238168^2 .

It is a cyclic number.

It is not a de Polignac number, because 813441307249 - 233 = 804851372657 is a prime.

It is a super-3 number, since 3×8134413072493 (a number of 37 digits) contains 333 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 813441307199 and 813441307208.

It is not a weakly prime, because it can be changed into another prime (813421307249) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 406720653624 + 406720653625.

It is an arithmetic number, because the mean of its divisors is an integer number (406720653625).

Almost surely, 2813441307249 is an apocalyptic number.

It is an amenable number.

813441307249 is a deficient number, since it is larger than the sum of its proper divisors (1).

813441307249 is an equidigital number, since it uses as much as digits as its factorization.

813441307249 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 580608, while the sum is 46.

The spelling of 813441307249 in words is "eight hundred thirteen billion, four hundred forty-one million, three hundred seven thousand, two hundred forty-nine".