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8148404412553 is a prime number
BaseRepresentation
bin111011010010011001011…
…0000000010000010001001
31001211222110022110200020111
41312210302300002002021
52032000413012200203
625155154133354321
71500463025466106
oct166446260020211
931758408420214
108148404412553
11266179a953979
12ab72701989a1
13471511724122
14202556167aad
15e1e5a91826d
hex76932c02089

8148404412553 has 2 divisors, whose sum is σ = 8148404412554. Its totient is φ = 8148404412552.

The previous prime is 8148404412521. The next prime is 8148404412601. The reversal of 8148404412553 is 3552144048418.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 7597895319184 + 550509093369 = 2756428^2 + 741963^2 .

It is a cyclic number.

It is not a de Polignac number, because 8148404412553 - 25 = 8148404412521 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 8148404412497 and 8148404412506.

It is not a weakly prime, because it can be changed into another prime (8148404412853) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 4074202206276 + 4074202206277.

It is an arithmetic number, because the mean of its divisors is an integer number (4074202206277).

Almost surely, 28148404412553 is an apocalyptic number.

It is an amenable number.

8148404412553 is a deficient number, since it is larger than the sum of its proper divisors (1).

8148404412553 is an equidigital number, since it uses as much as digits as its factorization.

8148404412553 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 2457600, while the sum is 49.

The spelling of 8148404412553 in words is "eight trillion, one hundred forty-eight billion, four hundred four million, four hundred twelve thousand, five hundred fifty-three".