Base | Representation |
---|---|
bin | 10010100100111111110011… |
… | …100111001011000101110011 |
3 | 101201022010200201221020010011 |
4 | 102210333303213023011303 |
5 | 41202142422000114324 |
6 | 445435443101115351 |
7 | 23132103552532651 |
oct | 2244776347130563 |
9 | 351263621836104 |
10 | 81707250004339 |
11 | 24041939584253 |
12 | 91b74b4858b57 |
13 | 3678c6461528b |
14 | 162691b139dd1 |
15 | 96a5d69a6c94 |
hex | 4a4ff39cb173 |
81707250004339 has 2 divisors, whose sum is σ = 81707250004340. Its totient is φ = 81707250004338.
The previous prime is 81707250004321. The next prime is 81707250004349. The reversal of 81707250004339 is 93340005270718.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 81707250004339 - 237 = 81569811050867 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 81707250004292 and 81707250004301.
It is not a weakly prime, because it can be changed into another prime (81707250004309) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 40853625002169 + 40853625002170.
It is an arithmetic number, because the mean of its divisors is an integer number (40853625002170).
Almost surely, 281707250004339 is an apocalyptic number.
81707250004339 is a deficient number, since it is larger than the sum of its proper divisors (1).
81707250004339 is an equidigital number, since it uses as much as digits as its factorization.
81707250004339 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 1270080, while the sum is 49.
The spelling of 81707250004339 in words is "eighty-one trillion, seven hundred seven billion, two hundred fifty million, four thousand, three hundred thirty-nine".
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