Base | Representation |
---|---|
bin | 10010101111010101100100… |
… | …100001111101000111000011 |
3 | 101210211001210011120112120101 |
4 | 102233111210201331013003 |
5 | 41300313140400044403 |
6 | 451142115431023231 |
7 | 23234330156435632 |
oct | 2257254441750703 |
9 | 353731704515511 |
10 | 82417814065603 |
11 | 24296220459495 |
12 | 92b115b20ab17 |
13 | 36cac74594133 |
14 | 164d087473519 |
15 | 97dd231db71d |
hex | 4af56487d1c3 |
82417814065603 has 2 divisors, whose sum is σ = 82417814065604. Its totient is φ = 82417814065602.
The previous prime is 82417814065577. The next prime is 82417814065607. The reversal of 82417814065603 is 30656041871428.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 82417814065603 - 221 = 82417811968451 is a prime.
It is not a weakly prime, because it can be changed into another prime (82417814065607) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 41208907032801 + 41208907032802.
It is an arithmetic number, because the mean of its divisors is an integer number (41208907032802).
Almost surely, 282417814065603 is an apocalyptic number.
82417814065603 is a deficient number, since it is larger than the sum of its proper divisors (1).
82417814065603 is an equidigital number, since it uses as much as digits as its factorization.
82417814065603 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 7741440, while the sum is 55.
The spelling of 82417814065603 in words is "eighty-two trillion, four hundred seventeen billion, eight hundred fourteen million, sixty-five thousand, six hundred three".
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