Search a number
-
+
830307527851 is a prime number
BaseRepresentation
bin11000001010100100010…
…11110110110010101011
32221101011120002200021011
430011102023312302223
5102100432211342401
61433234335524351
7113662536352354
oct14052213666253
92841146080234
10830307527851
112a0149a53a7a
12114b043896b7
13603b3c76ac9
142c289582d2b
15168e8e15451
hexc1522f6cab

830307527851 has 2 divisors, whose sum is σ = 830307527852. Its totient is φ = 830307527850.

The previous prime is 830307527773. The next prime is 830307527891. The reversal of 830307527851 is 158725703038.

830307527851 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a strong prime.

It is a cyclic number.

It is not a de Polignac number, because 830307527851 - 213 = 830307519659 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 830307527795 and 830307527804.

It is not a weakly prime, because it can be changed into another prime (830307527891) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 415153763925 + 415153763926.

It is an arithmetic number, because the mean of its divisors is an integer number (415153763926).

Almost surely, 2830307527851 is an apocalyptic number.

830307527851 is a deficient number, since it is larger than the sum of its proper divisors (1).

830307527851 is an equidigital number, since it uses as much as digits as its factorization.

830307527851 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 1411200, while the sum is 49.

The spelling of 830307527851 in words is "eight hundred thirty billion, three hundred seven million, five hundred twenty-seven thousand, eight hundred fifty-one".