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83109970944000 = 213345372112132
BaseRepresentation
bin10010111001011010001100…
…010010111010000000000000
3101220021020100202212002010000
4102321122030102322000000
541343133210030202000
6452432105451040000
723335332362020500
oct2271321422720000
9356236322762100
1083109970944000
1124532816a1a800
1293a3329140000
13374b30cb57900
141674788c69a00
15991d33936000
hex4b968c4ba000

83109970944000 has 7560 divisors, whose sum is σ = 429023405895084. Its totient is φ = 15941173248000.

The previous prime is 83109970943999. The next prime is 83109970944001. The reversal of 83109970944000 is 44907990138.

It is a powerful number, because all its prime factors have an exponent greater than 1 and also an Achilles number because it is not a perfect power.

83109970944000 is a `hidden beast` number, since 8 + 3 + 109 + 97 + 0 + 9 + 440 + 0 + 0 = 666.

It is an interprime number because it is at equal distance from previous prime (83109970943999) and next prime (83109970944001).

It can be written as a sum of positive squares in 6 ways, for example, as 3637167722496 + 79472803221504 = 1907136^2 + 8914752^2 .

It is a tau number, because it is divible by the number of its divisors (7560).

It is a super-2 number, since 2×831099709440002 (a number of 29 digits) contains 22 as substring.

It is a Harshad number since it is a multiple of its sum of digits (54).

It is not an unprimeable number, because it can be changed into a prime (83109970944001) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written in 539 ways as a sum of consecutive naturals, for example, 6393074687994 + ... + 6393074688006.

Almost surely, 283109970944000 is an apocalyptic number.

83109970944000 is a gapful number since it is divisible by the number (80) formed by its first and last digit.

It is an amenable number.

It is a practical number, because each smaller number is the sum of distinct divisors of 83109970944000, and also a Zumkeller number, because its divisors can be partitioned in two sets with the same sum (214511702947542).

83109970944000 is an abundant number, since it is smaller than the sum of its proper divisors (345913434951084).

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

83109970944000 is a wasteful number, since it uses less digits than its factorization.

83109970944000 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 115 (or 41 counting only the distinct ones).

The product of its (nonzero) digits is 1959552, while the sum is 54.

The spelling of 83109970944000 in words is "eighty-three trillion, one hundred nine billion, nine hundred seventy million, nine hundred forty-four thousand".