Base | Representation |
---|---|
bin | 10010111001100100100011… |
… | …101110010110011101000100 |
3 | 101220022022002110211111010011 |
4 | 102321210203232112131010 |
5 | 41343324003431321034 |
6 | 452441150140040004 |
7 | 23336205244430632 |
oct | 2271444356263504 |
9 | 356268073744104 |
10 | 83121101432644 |
11 | 24537508883650 |
12 | 93a5514833004 |
13 | 374c394b0c272 |
14 | 16751231c6352 |
15 | 992285b9d864 |
hex | 4b9923b96744 |
83121101432644 has 24 divisors (see below), whose sum is σ = 158687879279328. Its totient is φ = 37781809266240.
The previous prime is 83121101432641. The next prime is 83121101432657. The reversal of 83121101432644 is 44623410112138.
It is a junction number, because it is equal to n+sod(n) for n = 83121101432597 and 83121101432606.
It is not an unprimeable number, because it can be changed into a prime (83121101432641) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (23) of ones.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 9430017 + ... + 15973960.
It is an arithmetic number, because the mean of its divisors is an integer number (6611994969972).
Almost surely, 283121101432644 is an apocalyptic number.
It is an amenable number.
83121101432644 is a deficient number, since it is larger than the sum of its proper divisors (75566777846684).
83121101432644 is a wasteful number, since it uses less digits than its factorization.
83121101432644 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 25478355 (or 25478353 counting only the distinct ones).
The product of its (nonzero) digits is 110592, while the sum is 40.
The spelling of 83121101432644 in words is "eighty-three trillion, one hundred twenty-one billion, one hundred one million, four hundred thirty-two thousand, six hundred forty-four".
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