Base | Representation |
---|---|
bin | 111100101100011001010… |
… | …0100110100010010000001 |
3 | 1002112110022200011211110112 |
4 | 1321120302210310102001 |
5 | 2043132222300012321 |
6 | 25424040153041105 |
7 | 1520444324415251 |
oct | 171306244642201 |
9 | 32473280154415 |
10 | 8341675000961 |
11 | 2726759086595 |
12 | b2880a0b6195 |
13 | 48680280ac43 |
14 | 20ba4c607961 |
15 | e6ebd1c2a5b |
hex | 79632934481 |
8341675000961 has 2 divisors, whose sum is σ = 8341675000962. Its totient is φ = 8341675000960.
The previous prime is 8341675000949. The next prime is 8341675001017. The reversal of 8341675000961 is 1690005761438.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 7969018473025 + 372656527936 = 2822945^2 + 610456^2 .
It is a cyclic number.
It is not a de Polignac number, because 8341675000961 - 222 = 8341670806657 is a prime.
It is a super-3 number, since 3×83416750009613 (a number of 40 digits) contains 333 as substring.
It is not a weakly prime, because it can be changed into another prime (8341675000861) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 4170837500480 + 4170837500481.
It is an arithmetic number, because the mean of its divisors is an integer number (4170837500481).
Almost surely, 28341675000961 is an apocalyptic number.
It is an amenable number.
8341675000961 is a deficient number, since it is larger than the sum of its proper divisors (1).
8341675000961 is an equidigital number, since it uses as much as digits as its factorization.
8341675000961 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 1088640, while the sum is 50.
The spelling of 8341675000961 in words is "eight trillion, three hundred forty-one billion, six hundred seventy-five million, nine hundred sixty-one", and thus it is an aban number.
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