Base | Representation |
---|---|
bin | 100110111001010010… |
… | …0000101010001101111 |
3 | 21222121002201210022121 |
4 | 1031302210011101233 |
5 | 2332030232040142 |
6 | 102212125253411 |
7 | 6014602011631 |
oct | 1156244052157 |
9 | 258532653277 |
10 | 83526440047 |
11 | 32472552746 |
12 | 14230a04267 |
13 | 7b518cac2b |
14 | 408525aa51 |
15 | 228cd9ec67 |
hex | 137290546f |
83526440047 has 4 divisors (see below), whose sum is σ = 83568776760. Its totient is φ = 83484103336.
The previous prime is 83526440029. The next prime is 83526440071. The reversal of 83526440047 is 74004462538.
It is a semiprime because it is the product of two primes, and also an emirpimes, since its reverse is a distinct semiprime: 74004462538 = 2 ⋅37002231269.
It is a cyclic number.
It is not a de Polignac number, because 83526440047 - 211 = 83526437999 is a prime.
It is a Duffinian number.
It is a junction number, because it is equal to n+sod(n) for n = 83526439985 and 83526440012.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (83526440087) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 21165397 + ... + 21169342.
It is an arithmetic number, because the mean of its divisors is an integer number (20892194190).
Almost surely, 283526440047 is an apocalyptic number.
83526440047 is a deficient number, since it is larger than the sum of its proper divisors (42336713).
83526440047 is a wasteful number, since it uses less digits than its factorization.
83526440047 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 42336712.
The product of its (nonzero) digits is 645120, while the sum is 43.
The spelling of 83526440047 in words is "eighty-three billion, five hundred twenty-six million, four hundred forty thousand, forty-seven".
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