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83613044365273 is a prime number
BaseRepresentation
bin10011000000101110101101…
…110011101101011111011001
3101222001022212211020202202001
4103000232231303231133121
541424404003324142043
6453455145144241001
723416562120366053
oct2300565563553731
9358038784222661
1083613044365273
1124707102836085
129464927470161
1337868a3955a47
141690c703288d3
1599ee792b274d
hex4c0badced7d9

83613044365273 has 2 divisors, whose sum is σ = 83613044365274. Its totient is φ = 83613044365272.

The previous prime is 83613044365247. The next prime is 83613044365373. The reversal of 83613044365273 is 37256344031638.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 68347207614169 + 15265836751104 = 8267237^2 + 3907152^2 .

It is a cyclic number.

It is not a de Polignac number, because 83613044365273 - 225 = 83613010810841 is a prime.

It is a super-3 number, since 3×836130443652733 (a number of 43 digits) contains 333 as substring. Note that it is a super-d number also for d = 2.

It is not a weakly prime, because it can be changed into another prime (83613044365243) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 41806522182636 + 41806522182637.

It is an arithmetic number, because the mean of its divisors is an integer number (41806522182637).

Almost surely, 283613044365273 is an apocalyptic number.

It is an amenable number.

83613044365273 is a deficient number, since it is larger than the sum of its proper divisors (1).

83613044365273 is an equidigital number, since it uses as much as digits as its factorization.

83613044365273 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 26127360, while the sum is 55.

The spelling of 83613044365273 in words is "eighty-three trillion, six hundred thirteen billion, forty-four million, three hundred sixty-five thousand, two hundred seventy-three".