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841312000000 = 2115661431
BaseRepresentation
bin11000011111000100001…
…10100101100000000000
32222102120110221210010201
430033202012211200000
5102241001333000000
61442254323534544
7114532332002503
oct14174206454000
92872513853121
10841312000000
112a488676685a
1211707582a454
1361448aa8ba4
142ca10c9913a
1516d4008996a
hexc3e21a5800

841312000000 has 336 divisors, whose sum is σ = 2142169454880. Its totient is φ = 330240000000.

The previous prime is 841311999989. The next prime is 841312000021. The reversal of 841312000000 is 213148.

It is a congruent number.

It is an unprimeable number.

It is a polite number, since it can be written in 27 ways as a sum of consecutive naturals, for example, 1951999785 + ... + 1952000215.

It is an arithmetic number, because the mean of its divisors is an integer number (6375504330).

Almost surely, 2841312000000 is an apocalyptic number.

841312000000 is a gapful number since it is divisible by the number (80) formed by its first and last digit.

It is an amenable number.

It is a practical number, because each smaller number is the sum of distinct divisors of 841312000000, and also a Zumkeller number, because its divisors can be partitioned in two sets with the same sum (1071084727440).

841312000000 is an abundant number, since it is smaller than the sum of its proper divisors (1300857454880).

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

841312000000 is an frugal number, since it uses more digits than its factorization.

841312000000 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 544 (or 499 counting only the distinct ones).

The product of its (nonzero) digits is 192, while the sum is 19.

Adding to 841312000000 its reverse (213148), we get a palindrome (841312213148).

The spelling of 841312000000 in words is "eight hundred forty-one billion, three hundred twelve million", and thus it is an aban number.