Base | Representation |
---|---|
bin | 11000100000100101101… |
… | …11011000111110100011 |
3 | 2222111200111100120112120 |
4 | 30100102313120332203 |
5 | 102244140301201011 |
6 | 1442511430355323 |
7 | 114561524513205 |
oct | 14202267307643 |
9 | 2874614316476 |
10 | 842130100131 |
11 | 2a516653a571 |
12 | 1172637bbb43 |
13 | 615494284c8 |
14 | 2ca8b7b6775 |
15 | 16d8bcd9a06 |
hex | c412dd8fa3 |
842130100131 has 64 divisors (see below), whose sum is σ = 1236006912000. Its totient is φ = 508032051840.
The previous prime is 842130100129. The next prime is 842130100153. The reversal of 842130100131 is 131001031248.
842130100131 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It is not a de Polignac number, because 842130100131 - 21 = 842130100129 is a prime.
It is a super-2 number, since 2×8421301001312 (a number of 25 digits) contains 22 as substring.
It is not an unprimeable number, because it can be changed into a prime (842130100111) by changing a digit.
It is a polite number, since it can be written in 63 ways as a sum of consecutive naturals, for example, 42481140 + ... + 42500958.
It is an arithmetic number, because the mean of its divisors is an integer number (19312608000).
Almost surely, 2842130100131 is an apocalyptic number.
842130100131 is a deficient number, since it is larger than the sum of its proper divisors (393876811869).
842130100131 is a wasteful number, since it uses less digits than its factorization.
842130100131 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 20184.
The product of its (nonzero) digits is 576, while the sum is 24.
Adding to 842130100131 its reverse (131001031248), we get a palindrome (973131131379).
The spelling of 842130100131 in words is "eight hundred forty-two billion, one hundred thirty million, one hundred thousand, one hundred thirty-one".
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