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845540131 is a prime number
BaseRepresentation
bin110010011001011…
…110101100100011
32011221000220000011
4302121132230203
53212424241011
6215522505351
726644654402
oct6231365443
92157026004
10845540131
113a43158a7
121b7205257
13106239307
1480421639
154e370621
hex3265eb23

845540131 has 2 divisors, whose sum is σ = 845540132. Its totient is φ = 845540130.

The previous prime is 845540119. The next prime is 845540149. The reversal of 845540131 is 131045548.

It is a weak prime.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-845540131 is a prime.

It is a super-2 number, since 2×8455401312 = 1429876226262994322, which contains 22 as substring.

It is a Chen prime.

It is a junction number, because it is equal to n+sod(n) for n = 845540093 and 845540102.

It is not a weakly prime, because it can be changed into another prime (845540231) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 422770065 + 422770066.

It is an arithmetic number, because the mean of its divisors is an integer number (422770066).

Almost surely, 2845540131 is an apocalyptic number.

845540131 is a deficient number, since it is larger than the sum of its proper divisors (1).

845540131 is an equidigital number, since it uses as much as digits as its factorization.

845540131 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 9600, while the sum is 31.

The square root of 845540131 is about 29078.1727589613. The cubic root of 845540131 is about 945.6085890636.

Adding to 845540131 its reverse (131045548), we get a palindrome (976585679).

The spelling of 845540131 in words is "eight hundred forty-five million, five hundred forty thousand, one hundred thirty-one".