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84811002051 = 328270334017
BaseRepresentation
bin100111011111100100…
…0010011000011000011
322002220121212022010010
41032333020103003003
52342143104031201
6102543414040003
76061460423436
oct1167710230303
9262817768103
1084811002051
1132a71666136
121452b049003
137cc7a8c0a9
144167abd81d
152315a40bd6
hex13bf2130c3

84811002051 has 4 divisors (see below), whose sum is σ = 113081336072. Its totient is φ = 56540668032.

The previous prime is 84811002037. The next prime is 84811002083. The reversal of 84811002051 is 15020011848.

It is a happy number.

It is a semiprime because it is the product of two primes.

It is a de Polignac number, because none of the positive numbers 2k-84811002051 is a prime.

It is a super-3 number, since 3×848110020513 (a number of 34 digits) contains 333 as substring.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (84811002091) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 14135167006 + ... + 14135167011.

It is an arithmetic number, because the mean of its divisors is an integer number (28270334018).

Almost surely, 284811002051 is an apocalyptic number.

84811002051 is a deficient number, since it is larger than the sum of its proper divisors (28270334021).

84811002051 is a wasteful number, since it uses less digits than its factorization.

84811002051 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 28270334020.

The product of its (nonzero) digits is 2560, while the sum is 30.

Adding to 84811002051 its reverse (15020011848), we get a palindrome (99831013899).

The spelling of 84811002051 in words is "eighty-four billion, eight hundred eleven million, two thousand, fifty-one".

Divisors: 1 3 28270334017 84811002051