Base | Representation |
---|---|
bin | 100111100101100010… |
… | …0000010001101001001 |
3 | 22010102120120222021101 |
4 | 1033023010002031021 |
5 | 2343100332223311 |
6 | 103015325141401 |
7 | 6066441241306 |
oct | 1171304021511 |
9 | 263376528241 |
10 | 85011211081 |
11 | 33064681145 |
12 | 145860ba861 |
13 | 802a3ba584 |
14 | 41865180ad |
15 | 23283dbec1 |
hex | 13cb102349 |
85011211081 has 2 divisors, whose sum is σ = 85011211082. Its totient is φ = 85011211080.
The previous prime is 85011211049. The next prime is 85011211091. The reversal of 85011211081 is 18011211058.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 56489405625 + 28521805456 = 237675^2 + 168884^2 .
It is a cyclic number.
It is not a de Polignac number, because 85011211081 - 25 = 85011211049 is a prime.
It is a super-3 number, since 3×850112110813 (a number of 34 digits) contains 333 as substring. Note that it is a super-d number also for d = 2.
It is not a weakly prime, because it can be changed into another prime (85011211091) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 42505605540 + 42505605541.
It is an arithmetic number, because the mean of its divisors is an integer number (42505605541).
Almost surely, 285011211081 is an apocalyptic number.
It is an amenable number.
85011211081 is a deficient number, since it is larger than the sum of its proper divisors (1).
85011211081 is an equidigital number, since it uses as much as digits as its factorization.
85011211081 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 640, while the sum is 28.
The spelling of 85011211081 in words is "eighty-five billion, eleven million, two hundred eleven thousand, eighty-one".
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