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851021164448713 is a prime number
BaseRepresentation
bin1100000101111111111100111…
…0001101000000101111001001
311010121012211101011202022111101
43001133333032031000233021
51343021112321044324323
612213545420433301401
7344153151540031216
oct30137771615005711
94117184334668441
10851021164448713
1122718605a2898a5
127b54572a104861
132a6b1c4a48972b
1411021903702b0d
15685c030715dad
hex305ffce340bc9

851021164448713 has 2 divisors, whose sum is σ = 851021164448714. Its totient is φ = 851021164448712.

The previous prime is 851021164448647. The next prime is 851021164448723. The reversal of 851021164448713 is 317844461120158.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 827880177230649 + 23140987218064 = 28772907^2 + 4810508^2 .

It is a cyclic number.

It is not a de Polignac number, because 851021164448713 - 213 = 851021164440521 is a prime.

It is not a weakly prime, because it can be changed into another prime (851021164448723) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 425510582224356 + 425510582224357.

It is an arithmetic number, because the mean of its divisors is an integer number (425510582224357).

Almost surely, 2851021164448713 is an apocalyptic number.

It is an amenable number.

851021164448713 is a deficient number, since it is larger than the sum of its proper divisors (1).

851021164448713 is an equidigital number, since it uses as much as digits as its factorization.

851021164448713 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 5160960, while the sum is 55.

The spelling of 851021164448713 in words is "eight hundred fifty-one trillion, twenty-one billion, one hundred sixty-four million, four hundred forty-eight thousand, seven hundred thirteen".