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85107433 is a prime number
BaseRepresentation
bin1010001001010…
…10001011101001
312221010220110011
411010222023221
5133241414213
612240051521
72052254425
oct504521351
9187126404
1085107433
114404a524
1224603ba1
131482b038
14b435b85
15771203d
hex512a2e9

85107433 has 2 divisors, whose sum is σ = 85107434. Its totient is φ = 85107432.

The previous prime is 85107401. The next prime is 85107469. The reversal of 85107433 is 33470158.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 82664464 + 2442969 = 9092^2 + 1563^2 .

It is a cyclic number.

It is not a de Polignac number, because 85107433 - 25 = 85107401 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 85107395 and 85107404.

It is not a weakly prime, because it can be changed into another prime (85107133) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 42553716 + 42553717.

It is an arithmetic number, because the mean of its divisors is an integer number (42553717).

Almost surely, 285107433 is an apocalyptic number.

It is an amenable number.

85107433 is a deficient number, since it is larger than the sum of its proper divisors (1).

85107433 is an equidigital number, since it uses as much as digits as its factorization.

85107433 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 10080, while the sum is 31.

The square root of 85107433 is about 9225.3689899104. The cubic root of 85107433 is about 439.8681302479.

The spelling of 85107433 in words is "eighty-five million, one hundred seven thousand, four hundred thirty-three".