Base | Representation |
---|---|
bin | 11000110001011001100… |
… | …00100000111101101001 |
3 | 10000100222102020112122001 |
4 | 30120230300200331221 |
5 | 102421131014040131 |
6 | 1451003121331001 |
7 | 115331254240123 |
oct | 14305460407551 |
9 | 3010872215561 |
10 | 851154440041 |
11 | 2a8a77545724 |
12 | 118b61a96a61 |
13 | 62356c4b3c9 |
14 | 2d2a6126213 |
15 | 172191c3261 |
hex | c62cc20f69 |
851154440041 has 2 divisors, whose sum is σ = 851154440042. Its totient is φ = 851154440040.
The previous prime is 851154440011. The next prime is 851154440053. The reversal of 851154440041 is 140044451158.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 593670250000 + 257484190041 = 770500^2 + 507429^2 .
It is a cyclic number.
It is not a de Polignac number, because 851154440041 - 229 = 850617569129 is a prime.
It is not a weakly prime, because it can be changed into another prime (851154440011) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 425577220020 + 425577220021.
It is an arithmetic number, because the mean of its divisors is an integer number (425577220021).
Almost surely, 2851154440041 is an apocalyptic number.
It is an amenable number.
851154440041 is a deficient number, since it is larger than the sum of its proper divisors (1).
851154440041 is an equidigital number, since it uses as much as digits as its factorization.
851154440041 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 51200, while the sum is 37.
Adding to 851154440041 its reverse (140044451158), we get a palindrome (991198891199).
The spelling of 851154440041 in words is "eight hundred fifty-one billion, one hundred fifty-four million, four hundred forty thousand, forty-one".
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