Base | Representation |
---|---|
bin | 11000110001111000101… |
… | …10011000111110101011 |
3 | 10000101122122110112112211 |
4 | 30120330112120332223 |
5 | 102422200000331201 |
6 | 1451045104145551 |
7 | 115340611551352 |
oct | 14307426307653 |
9 | 3011578415484 |
10 | 851416027051 |
11 | 2a90a1172937 |
12 | 1190156082b7 |
13 | 623991b9b15 |
14 | 2d2ccb7a999 |
15 | 17232145651 |
hex | c63c598fab |
851416027051 has 2 divisors, whose sum is σ = 851416027052. Its totient is φ = 851416027050.
The previous prime is 851416026997. The next prime is 851416027069. The reversal of 851416027051 is 150720614158.
It is a strong prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-851416027051 is a prime.
It is a super-2 number, since 2×8514160270512 (a number of 25 digits) contains 22 as substring.
It is a junction number, because it is equal to n+sod(n) for n = 851416026995 and 851416027013.
It is not a weakly prime, because it can be changed into another prime (851416927051) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 425708013525 + 425708013526.
It is an arithmetic number, because the mean of its divisors is an integer number (425708013526).
Almost surely, 2851416027051 is an apocalyptic number.
851416027051 is a deficient number, since it is larger than the sum of its proper divisors (1).
851416027051 is an equidigital number, since it uses as much as digits as its factorization.
851416027051 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 67200, while the sum is 40.
The spelling of 851416027051 in words is "eight hundred fifty-one billion, four hundred sixteen million, twenty-seven thousand, fifty-one".
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