Base | Representation |
---|---|
bin | 100111110001001001… |
… | …1110000111001111011 |
3 | 22011102202102222212222 |
4 | 1033202103300321323 |
5 | 2344400202213431 |
6 | 103122140154255 |
7 | 6112215211652 |
oct | 1174223607173 |
9 | 264382388788 |
10 | 85401210491 |
11 | 33244836503 |
12 | 1467483898b |
13 | 8090139c5c |
14 | 41c2238199 |
15 | 234c77757b |
hex | 13e24f0e7b |
85401210491 has 2 divisors, whose sum is σ = 85401210492. Its totient is φ = 85401210490.
The previous prime is 85401210413. The next prime is 85401210497. The reversal of 85401210491 is 19401210458.
It is a strong prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-85401210491 is a prime.
It is a super-2 number, since 2×854012104912 (a number of 23 digits) contains 22 as substring.
It is not a weakly prime, because it can be changed into another prime (85401210497) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 42700605245 + 42700605246.
It is an arithmetic number, because the mean of its divisors is an integer number (42700605246).
Almost surely, 285401210491 is an apocalyptic number.
85401210491 is a deficient number, since it is larger than the sum of its proper divisors (1).
85401210491 is an equidigital number, since it uses as much as digits as its factorization.
85401210491 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 11520, while the sum is 35.
The spelling of 85401210491 in words is "eighty-five billion, four hundred one million, two hundred ten thousand, four hundred ninety-one".
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