Search a number
-
+
85557301 = 509168089
BaseRepresentation
bin1010001100110…
…00000000110101
312221222202112221
411012120000311
5133400313201
612253442341
72056140124
oct506300065
9187882487
1085557301
1144327515
12247a03b1
1314957a2b
14b511abb
1577a04a1
hex5198035

85557301 has 4 divisors (see below), whose sum is σ = 85725900. Its totient is φ = 85388704.

The previous prime is 85557299. The next prime is 85557331. The reversal of 85557301 is 10375558.

It is a semiprime because it is the product of two primes.

It can be written as a sum of positive squares in 2 ways, for example, as 32194276 + 53363025 = 5674^2 + 7305^2 .

It is a cyclic number.

It is not a de Polignac number, because 85557301 - 21 = 85557299 is a prime.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (85557331) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 83536 + ... + 84553.

It is an arithmetic number, because the mean of its divisors is an integer number (21431475).

Almost surely, 285557301 is an apocalyptic number.

It is an amenable number.

85557301 is a deficient number, since it is larger than the sum of its proper divisors (168599).

85557301 is a wasteful number, since it uses less digits than its factorization.

85557301 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 168598.

The product of its (nonzero) digits is 21000, while the sum is 34.

The square root of 85557301 is about 9249.7189687039. The cubic root of 85557301 is about 440.6417992757.

It can be divided in two parts, 85557 and 301, that added together give a palindrome (85858).

The spelling of 85557301 in words is "eighty-five million, five hundred fifty-seven thousand, three hundred one".

Divisors: 1 509 168089 85557301