Base | Representation |
---|---|
bin | 100111110111110101… |
… | …0010110111101111011 |
3 | 22012000100222201222211 |
4 | 1033233222112331323 |
5 | 2400330030043441 |
6 | 103200301555551 |
7 | 6120605336362 |
oct | 1175752267573 |
9 | 265010881884 |
10 | 85625237371 |
11 | 3334a23a193 |
12 | 14717875bb7 |
13 | 80c768753b |
14 | 4203cb27d9 |
15 | 236227aa81 |
hex | 13efa96f7b |
85625237371 has 2 divisors, whose sum is σ = 85625237372. Its totient is φ = 85625237370.
The previous prime is 85625237359. The next prime is 85625237381. The reversal of 85625237371 is 17373252658.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 85625237371 - 211 = 85625235323 is a prime.
It is a super-3 number, since 3×856252373713 (a number of 34 digits) contains 333 as substring.
It is not a weakly prime, because it can be changed into another prime (85625237381) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 42812618685 + 42812618686.
It is an arithmetic number, because the mean of its divisors is an integer number (42812618686).
Almost surely, 285625237371 is an apocalyptic number.
85625237371 is a deficient number, since it is larger than the sum of its proper divisors (1).
85625237371 is an equidigital number, since it uses as much as digits as its factorization.
85625237371 is an evil number, because the sum of its binary digits is even.
The product of its digits is 2116800, while the sum is 49.
The spelling of 85625237371 in words is "eighty-five billion, six hundred twenty-five million, two hundred thirty-seven thousand, three hundred seventy-one".
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