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85755587879993 is a prime number
BaseRepresentation
bin10011011111111010000111…
…010110100110010000111001
3102020122011011100212102201012
4103133322013112212100321
542220004420444124433
6502215323451403305
724030431260646213
oct2337720726462071
9366564140772635
1085755587879993
1125362816795289
129750010a53535
1338b0942a05aa5
1417268421435b3
159daa76435848
hex4dfe875a6439

85755587879993 has 2 divisors, whose sum is σ = 85755587879994. Its totient is φ = 85755587879992.

The previous prime is 85755587879971. The next prime is 85755587880013. The reversal of 85755587879993 is 39997878555758.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 64379649358249 + 21375938521744 = 8023693^2 + 4623412^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-85755587879993 is a prime.

It is a super-4 number, since 4×857555878799934 (a number of 57 digits) contains 4444 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 85755587879896 and 85755587879905.

It is not a weakly prime, because it can be changed into another prime (85755587879393) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 42877793939996 + 42877793939997.

It is an arithmetic number, because the mean of its divisors is an integer number (42877793939997).

Almost surely, 285755587879993 is an apocalyptic number.

It is an amenable number.

85755587879993 is a deficient number, since it is larger than the sum of its proper divisors (1).

85755587879993 is an equidigital number, since it uses as much as digits as its factorization.

85755587879993 is an evil number, because the sum of its binary digits is even.

The product of its digits is 240045120000, while the sum is 95.

The spelling of 85755587879993 in words is "eighty-five trillion, seven hundred fifty-five billion, five hundred eighty-seven million, eight hundred seventy-nine thousand, nine hundred ninety-three".