Base | Representation |
---|---|
bin | 100111111100010110… |
… | …1110010011111011001 |
3 | 22012101221210202112121 |
4 | 1033320231302133121 |
5 | 2401132421201411 |
6 | 103223325341241 |
7 | 6124431405346 |
oct | 1177055623731 |
9 | 265357722477 |
10 | 85777131481 |
11 | 33417a55508 |
12 | 1475a707821 |
13 | 811cc9a602 |
14 | 421a1317cd |
15 | 2370781571 |
hex | 13f8b727d9 |
85777131481 has 2 divisors, whose sum is σ = 85777131482. Its totient is φ = 85777131480.
The previous prime is 85777131383. The next prime is 85777131493. The reversal of 85777131481 is 18413177758.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 83706062400 + 2071069081 = 289320^2 + 45509^2 .
It is a cyclic number.
It is not a de Polignac number, because 85777131481 - 227 = 85642913753 is a prime.
It is a super-2 number, since 2×857771314812 (a number of 23 digits) contains 22 as substring.
It is not a weakly prime, because it can be changed into another prime (85777131281) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (23) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 42888565740 + 42888565741.
It is an arithmetic number, because the mean of its divisors is an integer number (42888565741).
Almost surely, 285777131481 is an apocalyptic number.
It is an amenable number.
85777131481 is a deficient number, since it is larger than the sum of its proper divisors (1).
85777131481 is an equidigital number, since it uses as much as digits as its factorization.
85777131481 is an odious number, because the sum of its binary digits is odd.
The product of its digits is 1317120, while the sum is 52.
The spelling of 85777131481 in words is "eighty-five billion, seven hundred seventy-seven million, one hundred thirty-one thousand, four hundred eighty-one".
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