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86116829932457 is a prime number
BaseRepresentation
bin10011100101001010100011…
…000011101010101110101001
3102021220200120221112001212122
4103211022203003222232221
542241414231430314312
6503053305302321025
724065510216511512
oct2345124303525651
9367820527461778
1086116829932457
1125491a40487a85
1297aa028129175
133908a226bab5c
14173a110a93a09
159e516a3dcb72
hex4e52a30eaba9

86116829932457 has 2 divisors, whose sum is σ = 86116829932458. Its totient is φ = 86116829932456.

The previous prime is 86116829932421. The next prime is 86116829932481. The reversal of 86116829932457 is 75423992861168.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 67536773141776 + 18580056790681 = 8218076^2 + 4310459^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-86116829932457 is a prime.

It is a super-2 number, since 2×861168299324572 (a number of 29 digits) contains 22 as substring.

It is not a weakly prime, because it can be changed into another prime (86116829932417) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 43058414966228 + 43058414966229.

It is an arithmetic number, because the mean of its divisors is an integer number (43058414966229).

Almost surely, 286116829932457 is an apocalyptic number.

It is an amenable number.

86116829932457 is a deficient number, since it is larger than the sum of its proper divisors (1).

86116829932457 is an equidigital number, since it uses as much as digits as its factorization.

86116829932457 is an odious number, because the sum of its binary digits is odd.

The product of its digits is 313528320, while the sum is 71.

The spelling of 86116829932457 in words is "eighty-six trillion, one hundred sixteen billion, eight hundred twenty-nine million, nine hundred thirty-two thousand, four hundred fifty-seven".