Base | Representation |
---|---|
bin | 11001000100001101010… |
… | …01111000111110001001 |
3 | 10001100001011200120121211 |
4 | 30202012221320332021 |
5 | 103102321130244101 |
6 | 1455353131533121 |
7 | 116136433130023 |
oct | 14420651707611 |
9 | 3040034616554 |
10 | 861252587401 |
11 | 3022896a6258 |
12 | 11aabb8ba1a1 |
13 | 632a608102b |
14 | 2d983317013 |
15 | 1760a9bbc51 |
hex | c886a78f89 |
861252587401 has 2 divisors, whose sum is σ = 861252587402. Its totient is φ = 861252587400.
The previous prime is 861252587357. The next prime is 861252587417. The reversal of 861252587401 is 104785252168.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 767998086025 + 93254501376 = 876355^2 + 305376^2 .
It is a cyclic number.
It is not a de Polignac number, because 861252587401 - 237 = 723813633929 is a prime.
It is not a weakly prime, because it can be changed into another prime (861252587471) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (19) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 430626293700 + 430626293701.
It is an arithmetic number, because the mean of its divisors is an integer number (430626293701).
Almost surely, 2861252587401 is an apocalyptic number.
It is an amenable number.
861252587401 is a deficient number, since it is larger than the sum of its proper divisors (1).
861252587401 is an equidigital number, since it uses as much as digits as its factorization.
861252587401 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 1075200, while the sum is 49.
The spelling of 861252587401 in words is "eight hundred sixty-one billion, two hundred fifty-two million, five hundred eighty-seven thousand, four hundred one".
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