Search a number
-
+
87990404353 is a prime number
BaseRepresentation
bin101000111110010100…
…0110000010100000001
322102010012110200010221
41101330220300110001
52420201020414403
6104231111423041
76233325045055
oct1217450602401
9272105420127
1087990404353
1134353320145
1215077984a81
1383b3698427
14438a065c65
15244ec20dbd
hex147ca30501

87990404353 has 2 divisors, whose sum is σ = 87990404354. Its totient is φ = 87990404352.

The previous prime is 87990404323. The next prime is 87990404417. The reversal of 87990404353 is 35340409978.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 76602739984 + 11387664369 = 276772^2 + 106713^2 .

It is a cyclic number.

It is not a de Polignac number, because 87990404353 - 217 = 87990273281 is a prime.

It is a super-2 number, since 2×879904043532 (a number of 23 digits) contains 22 as substring.

It is a self number, because there is not a number n which added to its sum of digits gives 87990404353.

It is not a weakly prime, because it can be changed into another prime (87990404303) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 43995202176 + 43995202177.

It is an arithmetic number, because the mean of its divisors is an integer number (43995202177).

Almost surely, 287990404353 is an apocalyptic number.

It is an amenable number.

87990404353 is a deficient number, since it is larger than the sum of its proper divisors (1).

87990404353 is an equidigital number, since it uses as much as digits as its factorization.

87990404353 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 3265920, while the sum is 52.

The spelling of 87990404353 in words is "eighty-seven billion, nine hundred ninety million, four hundred four thousand, three hundred fifty-three".