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89396253433 is a prime number
BaseRepresentation
bin101001101000001101…
…1101001001011111001
322112202011211012112101
41103100123221023321
52431040420102213
6105022411543401
76313215421324
oct1232033511371
9275664735471
1089396253433
1134a04944393
12153aa75ab61
138578a142a6
144480a5b7bb
1524d336dbdd
hex14d06e92f9

89396253433 has 2 divisors, whose sum is σ = 89396253434. Its totient is φ = 89396253432.

The previous prime is 89396253367. The next prime is 89396253491. The reversal of 89396253433 is 33435269398.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 63671942889 + 25724310544 = 252333^2 + 160388^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-89396253433 is a prime.

It is not a weakly prime, because it can be changed into another prime (89396253833) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 44698126716 + 44698126717.

It is an arithmetic number, because the mean of its divisors is an integer number (44698126717).

Almost surely, 289396253433 is an apocalyptic number.

It is an amenable number.

89396253433 is a deficient number, since it is larger than the sum of its proper divisors (1).

89396253433 is an equidigital number, since it uses as much as digits as its factorization.

89396253433 is an odious number, because the sum of its binary digits is odd.

The product of its digits is 12597120, while the sum is 55.

The spelling of 89396253433 in words is "eighty-nine billion, three hundred ninety-six million, two hundred fifty-three thousand, four hundred thirty-three".