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8956535134433 is a prime number
BaseRepresentation
bin1000001001010101101100…
…0110000101100011100001
31011201020101022222212211112
42002111123012011203201
52133220440443300213
631014324143353105
71613042201336465
oct202253306054341
934636338885745
108956535134433
112943499650327
121007a055b2795
134cc7a0022b23
1422d6da2a44a5
15107ea7927ea8
hex8255b1858e1

8956535134433 has 2 divisors, whose sum is σ = 8956535134434. Its totient is φ = 8956535134432.

The previous prime is 8956535134363. The next prime is 8956535134457. The reversal of 8956535134433 is 3344315356598.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 7785534126049 + 1171001008384 = 2790257^2 + 1082128^2 .

It is a cyclic number.

It is not a de Polignac number, because 8956535134433 - 222 = 8956530940129 is a prime.

It is a super-2 number, since 2×89565351344332 (a number of 27 digits) contains 22 as substring.

It is not a weakly prime, because it can be changed into another prime (8956535134733) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 4478267567216 + 4478267567217.

It is an arithmetic number, because the mean of its divisors is an integer number (4478267567217).

Almost surely, 28956535134433 is an apocalyptic number.

It is an amenable number.

8956535134433 is a deficient number, since it is larger than the sum of its proper divisors (1).

8956535134433 is an equidigital number, since it uses as much as digits as its factorization.

8956535134433 is an evil number, because the sum of its binary digits is even.

The product of its digits is 69984000, while the sum is 59.

The spelling of 8956535134433 in words is "eight trillion, nine hundred fifty-six billion, five hundred thirty-five million, one hundred thirty-four thousand, four hundred thirty-three".