900000041 has 2 divisors, whose sum is σ = 900000042. Its totient is φ = 900000040.

The previous prime is 900000011. The next prime is 900000053. The reversal of 900000041 is 140000009.

900000041 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 839782441 + 60217600 = 28979^2 + 7760^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2^k-900000041 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 899999971 and 900000025.

It is not a weakly prime, because it can be changed into another prime (900000011) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 450000020 + 450000021.

It is an arithmetic number, because the mean of its divisors is an integer number (450000021).

Almost surely, 2^900000041 is an apocalyptic number.

It is an amenable number.

900000041 is a deficient number, since it is larger than the sum of its proper divisors (1).

900000041 is an equidigital number, since it uses as much as digits as its factorization.

900000041 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 36, while the sum is 14.

The square root of 900000041 is about 30000.0006833333. Note that the first 3 decimals coincide. The cubic root of 900000041 is about 965.4893992668.

The spelling of 900000041 in words is "nine hundred million, forty-one", and thus it is an aban number.