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90009098041433 is a prime number
BaseRepresentation
bin10100011101110011100000…
…010100001011100001011001
3102210200210012210122200000212
4110131303200110023201121
543244202113044311213
6515233335300140505
724646641233533034
oct2435634024134131
9383623183580025
1090009098041433
112675270a34836a
12a118448997735
133b2ba8ab76bbc
14183266c13a01b
15a615234729a8
hex51dce050b859

90009098041433 has 2 divisors, whose sum is σ = 90009098041434. Its totient is φ = 90009098041432.

The previous prime is 90009098041397. The next prime is 90009098041517. The reversal of 90009098041433 is 33414089090009.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 76774694321689 + 13234403719744 = 8762117^2 + 3637912^2 .

It is a cyclic number.

It is not a de Polignac number, because 90009098041433 - 216 = 90009097975897 is a prime.

It is not a weakly prime, because it can be changed into another prime (90009098041033) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 45004549020716 + 45004549020717.

It is an arithmetic number, because the mean of its divisors is an integer number (45004549020717).

Almost surely, 290009098041433 is an apocalyptic number.

It is an amenable number.

90009098041433 is a deficient number, since it is larger than the sum of its proper divisors (1).

90009098041433 is an equidigital number, since it uses as much as digits as its factorization.

90009098041433 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 839808, while the sum is 50.

The spelling of 90009098041433 in words is "ninety trillion, nine billion, ninety-eight million, forty-one thousand, four hundred thirty-three".