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91316231024401 is a prime number
BaseRepresentation
bin10100110000110100110111…
…100000110010111100010001
3102222022202011010222012101101
4110300310313200302330101
543432111120120240101
6522114033012304401
725143244221550225
oct2460646740627421
9388282133865341
1091316231024401
1127106aa58931a9
12a2a9845012101
133bc5111998706
141879a2cb7a785
15a855286ce401
hex530d37832f11

91316231024401 has 2 divisors, whose sum is σ = 91316231024402. Its totient is φ = 91316231024400.

The previous prime is 91316231024303. The next prime is 91316231024419. The reversal of 91316231024401 is 10442013261319.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 46779307411600 + 44536923612801 = 6839540^2 + 6673599^2 .

It is an emirp because it is prime and its reverse (10442013261319) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 91316231024401 - 211 = 91316231022353 is a prime.

It is not a weakly prime, because it can be changed into another prime (91316231024201) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 45658115512200 + 45658115512201.

It is an arithmetic number, because the mean of its divisors is an integer number (45658115512201).

Almost surely, 291316231024401 is an apocalyptic number.

It is an amenable number.

91316231024401 is a deficient number, since it is larger than the sum of its proper divisors (1).

91316231024401 is an equidigital number, since it uses as much as digits as its factorization.

91316231024401 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 31104, while the sum is 37.

The spelling of 91316231024401 in words is "ninety-one trillion, three hundred sixteen billion, two hundred thirty-one million, twenty-four thousand, four hundred one".