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913444012193 is a prime number
BaseRepresentation
bin11010100101011011000…
…00011000000010100001
310020022202111001122220212
431102231200120002201
5104431213131342233
61535344055143505
7122664664665236
oct15225540300241
93208674048825
10913444012193
11322431371179
12129046674b95
13681a2b3c1cb
14322d4ad178d
1518b62937a48
hexd4ad8180a1

913444012193 has 2 divisors, whose sum is σ = 913444012194. Its totient is φ = 913444012192.

The previous prime is 913444012147. The next prime is 913444012237. The reversal of 913444012193 is 391210444319.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 474468859489 + 438975152704 = 688817^2 + 662552^2 .

It is a cyclic number.

It is not a de Polignac number, because 913444012193 - 228 = 913175576737 is a prime.

It is a super-2 number, since 2×9134440121932 (a number of 25 digits) contains 22 as substring.

It is a self number, because there is not a number n which added to its sum of digits gives 913444012193.

It is not a weakly prime, because it can be changed into another prime (913444015193) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 456722006096 + 456722006097.

It is an arithmetic number, because the mean of its divisors is an integer number (456722006097).

Almost surely, 2913444012193 is an apocalyptic number.

It is an amenable number.

913444012193 is a deficient number, since it is larger than the sum of its proper divisors (1).

913444012193 is an equidigital number, since it uses as much as digits as its factorization.

913444012193 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 93312, while the sum is 41.

The spelling of 913444012193 in words is "nine hundred thirteen billion, four hundred forty-four million, twelve thousand, one hundred ninety-three".