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91983617241713 is a prime number
BaseRepresentation
bin10100111010100010011010…
…110101001011001001110001
3110001200112210102212202221222
4110322202122311023021301
544024024422003213323
6523344405043154425
725242411533031221
oct2472423265131161
9401615712782858
1091983617241713
112734403aa1a18a
12a39705b375a15
133c430303b3092
1418a0060848081
15a97a894589c8
hex53a89ad4b271

91983617241713 has 2 divisors, whose sum is σ = 91983617241714. Its totient is φ = 91983617241712.

The previous prime is 91983617241709. The next prime is 91983617241727. The reversal of 91983617241713 is 31714271638919.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 82782483886144 + 9201133355569 = 9098488^2 + 3033337^2 .

It is a cyclic number.

It is not a de Polignac number, because 91983617241713 - 22 = 91983617241709 is a prime.

It is a super-2 number, since 2×919836172417132 (a number of 29 digits) contains 22 as substring.

It is not a weakly prime, because it can be changed into another prime (91983617241613) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 45991808620856 + 45991808620857.

It is an arithmetic number, because the mean of its divisors is an integer number (45991808620857).

Almost surely, 291983617241713 is an apocalyptic number.

It is an amenable number.

91983617241713 is a deficient number, since it is larger than the sum of its proper divisors (1).

91983617241713 is an equidigital number, since it uses as much as digits as its factorization.

91983617241713 is an odious number, because the sum of its binary digits is odd.

The product of its digits is 13716864, while the sum is 62.

The spelling of 91983617241713 in words is "ninety-one trillion, nine hundred eighty-three billion, six hundred seventeen million, two hundred forty-one thousand, seven hundred thirteen".