Base | Representation |
---|---|
bin | 10100111100111101001100… |
… | …110110110101110111001011 |
3 | 110002021102202220002220102002 |
4 | 110330331030312311313023 |
5 | 44034240304032433431 |
6 | 523553012314301215 |
7 | 25260414156556544 |
oct | 2474751466656713 |
9 | 402242686086362 |
10 | 92149812780491 |
11 | 273a8574a79324 |
12 | a403301a2780b |
13 | 3c558c80a027b |
14 | 18a810910b4cb |
15 | a9c064ca63cb |
hex | 53cf4cdb5dcb |
92149812780491 has 2 divisors, whose sum is σ = 92149812780492. Its totient is φ = 92149812780490.
The previous prime is 92149812780437. The next prime is 92149812780497. The reversal of 92149812780491 is 19408721894129.
It is a strong prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-92149812780491 is a prime.
It is a super-3 number, since 3×921498127804913 (a number of 43 digits) contains 333 as substring.
It is not a weakly prime, because it can be changed into another prime (92149812780497) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (29) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 46074906390245 + 46074906390246.
It is an arithmetic number, because the mean of its divisors is an integer number (46074906390246).
Almost surely, 292149812780491 is an apocalyptic number.
92149812780491 is a deficient number, since it is larger than the sum of its proper divisors (1).
92149812780491 is an equidigital number, since it uses as much as digits as its factorization.
92149812780491 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 20901888, while the sum is 65.
The spelling of 92149812780491 in words is "ninety-two trillion, one hundred forty-nine billion, eight hundred twelve million, seven hundred eighty thousand, four hundred ninety-one".
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