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92418134688001 is a prime number
BaseRepresentation
bin10101000000110111000110…
…000101101100000100000001
3110010020002100201010002122101
4111000313012011230010001
544103134314440004001
6524320145512110401
725315663350263353
oct2500670605540401
9403202321102571
1092418134688001
11274a13467718a1
12a447306395401
133c74cb9c8ac45
1418b70c0dc30d3
15aa401b363a01
hex540dc616c101

92418134688001 has 2 divisors, whose sum is σ = 92418134688002. Its totient is φ = 92418134688000.

The previous prime is 92418134687959. The next prime is 92418134688029. The reversal of 92418134688001 is 10088643181429.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 76576150608400 + 15841984079601 = 8750780^2 + 3980199^2 .

It is a cyclic number.

It is not a de Polignac number, because 92418134688001 - 225 = 92418101133569 is a prime.

It is a super-2 number, since 2×924181346880012 (a number of 29 digits) contains 22 as substring.

It is not a weakly prime, because it can be changed into another prime (92418134683001) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 46209067344000 + 46209067344001.

It is an arithmetic number, because the mean of its divisors is an integer number (46209067344001).

Almost surely, 292418134688001 is an apocalyptic number.

It is an amenable number.

92418134688001 is a deficient number, since it is larger than the sum of its proper divisors (1).

92418134688001 is an equidigital number, since it uses as much as digits as its factorization.

92418134688001 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 2654208, while the sum is 55.

The spelling of 92418134688001 in words is "ninety-two trillion, four hundred eighteen billion, one hundred thirty-four million, six hundred eighty-eight thousand, one".