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92491941769873 is a prime number
BaseRepresentation
bin10101000001111011110101…
…010101010111001010010001
3110010111010212110011100001021
4111001323311111113022101
544110341444043113443
6524414113402035441
725324215353156152
oct2501736525271221
9403433773140037
1092491941769873
112751a680961918
12a4596841a8b81
133c7bc5007c259
1418ba8c3491929
15aa5ddacdd9ed
hex541ef5557291

92491941769873 has 2 divisors, whose sum is σ = 92491941769874. Its totient is φ = 92491941769872.

The previous prime is 92491941769789. The next prime is 92491941769937. The reversal of 92491941769873 is 37896714919429.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 72636210745344 + 19855731024529 = 8522688^2 + 4455977^2 .

It is a cyclic number.

It is not a de Polignac number, because 92491941769873 - 245 = 57307569681041 is a prime.

It is a super-2 number, since 2×924919417698732 (a number of 29 digits) contains 22 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 92491941769793 and 92491941769802.

It is not a weakly prime, because it can be changed into another prime (92491941769673) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 46245970884936 + 46245970884937.

It is an arithmetic number, because the mean of its divisors is an integer number (46245970884937).

Almost surely, 292491941769873 is an apocalyptic number.

It is an amenable number.

92491941769873 is a deficient number, since it is larger than the sum of its proper divisors (1).

92491941769873 is an equidigital number, since it uses as much as digits as its factorization.

92491941769873 is an evil number, because the sum of its binary digits is even.

The product of its digits is 1481421312, while the sum is 79.

The spelling of 92491941769873 in words is "ninety-two trillion, four hundred ninety-one billion, nine hundred forty-one million, seven hundred sixty-nine thousand, eight hundred seventy-three".