Search a number
-
+
930211191841 is a prime number
BaseRepresentation
bin11011000100101001110…
…10000101110000100001
310021221001000110122100111
431202110322011300201
5110220033031114331
61551155542051321
7124130333446021
oct15422472056041
93257030418314
10930211191841
11329555a70438
12130345a19b41
1369945826699
14330458c7a81
15192e4970db1
hexd894e85c21

930211191841 has 2 divisors, whose sum is σ = 930211191842. Its totient is φ = 930211191840.

The previous prime is 930211191829. The next prime is 930211191859. The reversal of 930211191841 is 148191112039.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 930192736225 + 18455616 = 964465^2 + 4296^2 .

It is a cyclic number.

It is not a de Polignac number, because 930211191841 - 211 = 930211189793 is a prime.

It is a super-2 number, since 2×9302111918412 (a number of 25 digits) contains 22 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 930211191794 and 930211191803.

It is not a weakly prime, because it can be changed into another prime (930211191541) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 465105595920 + 465105595921.

It is an arithmetic number, because the mean of its divisors is an integer number (465105595921).

Almost surely, 2930211191841 is an apocalyptic number.

It is an amenable number.

930211191841 is a deficient number, since it is larger than the sum of its proper divisors (1).

930211191841 is an equidigital number, since it uses as much as digits as its factorization.

930211191841 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 15552, while the sum is 40.

The spelling of 930211191841 in words is "nine hundred thirty billion, two hundred eleven million, one hundred ninety-one thousand, eight hundred forty-one".