Base | Representation |
---|---|
bin | 101011011100111010… |
… | …1000010000000000000 |
3 | 22220212001222202000000 |
4 | 1112321311002000000 |
5 | 3012100333000000 |
6 | 110511132000000 |
7 | 6512233625142 |
oct | 1267165020000 |
9 | 286761882000 |
10 | 93312000000 |
11 | 3663421177a |
12 | 16102000000 |
13 | 8a510465ab |
14 | 4732b1cc92 |
15 | 2662000000 |
hex | 15b9d42000 |
93312000000 has 686 divisors, whose sum is σ = 349734175689. Its totient is φ = 24883200000.
The previous prime is 93311999987. The next prime is 93312000029. The reversal of 93312000000 is 21339.
It is a powerful number, because all its prime factors have an exponent greater than 1 and also an Achilles number because it is not a perfect power.
It can be written as a sum of positive squares in 4 ways, for example, as 15912308736 + 77399691264 = 126144^2 + 278208^2 .
It is an ABA number since it can be written as A⋅BA, here for A=2, B=216000.
It is a Harshad number since it is a multiple of its sum of digits (18).
It is an unprimeable number.
It is a pernicious number, because its binary representation contains a prime number (13) of ones.
It is a polite number, since it can be written in 48 ways as a sum of consecutive naturals, for example, 18662399998 + ... + 18662400002.
Almost surely, 293312000000 is an apocalyptic number.
93312000000 is a gapful number since it is divisible by the number (90) formed by its first and last digit.
It is an amenable number.
It is a practical number, because each smaller number is the sum of distinct divisors of 93312000000
93312000000 is an abundant number, since it is smaller than the sum of its proper divisors (256422175689).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
93312000000 is an frugal number, since it uses more digits than its factorization.
93312000000 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 74 (or 10 counting only the distinct ones).
The product of its (nonzero) digits is 162, while the sum is 18.
Multiplying 93312000000 by its sum of digits (18), we get a square (1679616000000 = 12960002).
93312000000 divided by its sum of digits (18) gives a square (5184000000 = 720002).
Multiplying 93312000000 by its product of nonzero digits (162), we get a square (15116544000000 = 38880002).
93312000000 divided by its product of nonzero digits (162) gives a square (576000000 = 240002).
Adding to 93312000000 its reverse (21339), we get a palindrome (93312021339).
The spelling of 93312000000 in words is "ninety-three billion, three hundred twelve million", and thus it is an aban number.
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