Base | Representation |
---|---|
bin | 10001100000101101… |
… | …10100000100111001 |
3 | 220021012001112100102 |
4 | 20300112310010321 |
5 | 123223203041213 |
6 | 4152512445145 |
7 | 451654030562 |
oct | 106026640471 |
9 | 26235045312 |
10 | 9401221433 |
11 | 3a9482089a |
12 | 19a45497b5 |
13 | b6a92b826 |
14 | 652817169 |
15 | 3a0532158 |
hex | 2305b4139 |
9401221433 has 2 divisors, whose sum is σ = 9401221434. Its totient is φ = 9401221432.
The previous prime is 9401221409. The next prime is 9401221439. The reversal of 9401221433 is 3341221049.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 4887128464 + 4514092969 = 69908^2 + 67187^2 .
It is a cyclic number.
It is not a de Polignac number, because 9401221433 - 220 = 9400172857 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 9401221396 and 9401221405.
It is not a weakly prime, because it can be changed into another prime (9401221439) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 4700610716 + 4700610717.
It is an arithmetic number, because the mean of its divisors is an integer number (4700610717).
Almost surely, 29401221433 is an apocalyptic number.
It is an amenable number.
9401221433 is a deficient number, since it is larger than the sum of its proper divisors (1).
9401221433 is an equidigital number, since it uses as much as digits as its factorization.
9401221433 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 5184, while the sum is 29.
The square root of 9401221433 is about 96959.8960034508. The cubic root of 9401221433 is about 2110.5457011170.
The spelling of 9401221433 in words is "nine billion, four hundred one million, two hundred twenty-one thousand, four hundred thirty-three".
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