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94017113 is a prime number
BaseRepresentation
bin1011001101010…
…01011001011001
320112220120020022
411212221121121
5143032021423
613155040225
72221063241
oct546513131
9215816208
1094017113
11490854a3
12275a0075
131662a538
14c6b4b21
1583c1dc8
hex59a9659

94017113 has 2 divisors, whose sum is σ = 94017114. Its totient is φ = 94017112.

The previous prime is 94017097. The next prime is 94017127. The reversal of 94017113 is 31171049.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 80496784 + 13520329 = 8972^2 + 3677^2 .

It is a cyclic number.

It is not a de Polignac number, because 94017113 - 24 = 94017097 is a prime.

It is a Chen prime.

It is not a weakly prime, because it can be changed into another prime (94017173) by changing a digit.

It is a good prime.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 47008556 + 47008557.

It is an arithmetic number, because the mean of its divisors is an integer number (47008557).

Almost surely, 294017113 is an apocalyptic number.

It is an amenable number.

94017113 is a deficient number, since it is larger than the sum of its proper divisors (1).

94017113 is an equidigital number, since it uses as much as digits as its factorization.

94017113 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 756, while the sum is 26.

The square root of 94017113 is about 9696.2422102586. The cubic root of 94017113 is about 454.7111849032.

The spelling of 94017113 in words is "ninety-four million, seventeen thousand, one hundred thirteen".