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94040113 is a prime number
BaseRepresentation
bin1011001101011…
…11000000110001
320112221201210011
411212233000301
5143033240423
613155334521
72221220266
oct546570061
9215851704
1094040113
11490a0802
12275b1441
1316637b4b
14c6bd26d
1583c8b0d
hex59af031

94040113 has 2 divisors, whose sum is σ = 94040114. Its totient is φ = 94040112.

The previous prime is 94040083. The next prime is 94040119. The reversal of 94040113 is 31104049.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 77580864 + 16459249 = 8808^2 + 4057^2 .

It is an emirp because it is prime and its reverse (31104049) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 94040113 - 29 = 94039601 is a prime.

It is not a weakly prime, because it can be changed into another prime (94040119) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (13) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 47020056 + 47020057.

It is an arithmetic number, because the mean of its divisors is an integer number (47020057).

Almost surely, 294040113 is an apocalyptic number.

It is an amenable number.

94040113 is a deficient number, since it is larger than the sum of its proper divisors (1).

94040113 is an equidigital number, since it uses as much as digits as its factorization.

94040113 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 432, while the sum is 22.

The square root of 94040113 is about 9697.4281642093. The cubic root of 94040113 is about 454.7482615027.

The spelling of 94040113 in words is "ninety-four million, forty thousand, one hundred thirteen".