94211159953 has 2 divisors, whose sum is σ = 94211159954. Its totient is φ = 94211159952.

The previous prime is 94211159921. The next prime is 94211159969. The reversal of 94211159953 is 35995111249.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 81061492369 + 13149667584 = 284713^2 + 114672^2 .

It is an emirp because it is prime and its reverse (35995111249) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 94211159953 - 2⁵ = 94211159921 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 94211159897 and 94211159906.

It is not a weakly prime, because it can be changed into another prime (94211151953) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 47105579976 + 47105579977.

It is an arithmetic number, because the mean of its divisors is an integer number (47105579977).

Almost surely, 2^94211159953 is an apocalyptic number.

It is an amenable number.

94211159953 is a deficient number, since it is larger than the sum of its proper divisors (1).

94211159953 is an equidigital number, since it uses as much as digits as its factorization.

94211159953 is an evil number, because the sum of its binary digits is even.

The product of its digits is 437400, while the sum is 49.

The spelling of 94211159953 in words is "ninety-four billion, two hundred eleven million, one hundred fifty-nine thousand, nine hundred fifty-three".