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9428412411433 is a prime number
BaseRepresentation
bin1000100100110011100100…
…1011000010111000101001
31020101100101021100020121201
42021030321023002320221
52213433342034131213
632015204115204201
71662115564120111
oct211147113027051
936340337306551
109428412411433
11300562700a794
1210833582a6661
135351319b46b2
142484a2510041
151153c46526dd
hex893392c2e29

9428412411433 has 2 divisors, whose sum is σ = 9428412411434. Its totient is φ = 9428412411432.

The previous prime is 9428412411409. The next prime is 9428412411437. The reversal of 9428412411433 is 3341142148249.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 5429100381849 + 3999312029584 = 2330043^2 + 1999828^2 .

It is a cyclic number.

It is not a de Polignac number, because 9428412411433 - 217 = 9428412280361 is a prime.

It is a super-2 number, since 2×94284124114332 (a number of 27 digits) contains 22 as substring.

It is not a weakly prime, because it can be changed into another prime (9428412411437) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 4714206205716 + 4714206205717.

It is an arithmetic number, because the mean of its divisors is an integer number (4714206205717).

Almost surely, 29428412411433 is an apocalyptic number.

It is an amenable number.

9428412411433 is a deficient number, since it is larger than the sum of its proper divisors (1).

9428412411433 is an equidigital number, since it uses as much as digits as its factorization.

9428412411433 is an odious number, because the sum of its binary digits is odd.

The product of its digits is 663552, while the sum is 46.

The spelling of 9428412411433 in words is "nine trillion, four hundred twenty-eight billion, four hundred twelve million, four hundred eleven thousand, four hundred thirty-three".