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94380095050651 is a prime number
BaseRepresentation
bin10101011101011010010100…
…000010100001001110011011
3110101011122112002200011010001
4111131122110002201032123
544332310413313110101
6532421341143433431
725610510511224554
oct2535322402411633
9411148462604101
1094380095050651
1128088412199063
12a7035b2a55877
13408800a649657
1419440417a332b
15ada0999dc901
hex55d6940a139b

94380095050651 has 2 divisors, whose sum is σ = 94380095050652. Its totient is φ = 94380095050650.

The previous prime is 94380095050627. The next prime is 94380095050691. The reversal of 94380095050651 is 15605059008349.

It is a weak prime.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-94380095050651 is a prime.

It is a super-3 number, since 3×943800950506513 (a number of 43 digits) contains 333 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 94380095050592 and 94380095050601.

It is not a weakly prime, because it can be changed into another prime (94380095050601) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 47190047525325 + 47190047525326.

It is an arithmetic number, because the mean of its divisors is an integer number (47190047525326).

Almost surely, 294380095050651 is an apocalyptic number.

94380095050651 is a deficient number, since it is larger than the sum of its proper divisors (1).

94380095050651 is an equidigital number, since it uses as much as digits as its factorization.

94380095050651 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 5832000, while the sum is 55.

The spelling of 94380095050651 in words is "ninety-four trillion, three hundred eighty billion, ninety-five million, fifty thousand, six hundred fifty-one".