945001011131 has 2 divisors, whose sum is σ = 945001011132. Its totient is φ = 945001011130.

The previous prime is 945001011083. The next prime is 945001011139. The reversal of 945001011131 is 131110100549.

It is a strong prime.

It is an emirp because it is prime and its reverse (131110100549) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 945001011131 - 2³⁸ = 670123104187 is a prime.

It is a super-2 number, since 2×945001011131² (a number of 25 digits) contains 22 as substring.

It is a self number, because there is not a number n which added to its sum of digits gives 945001011131.

It is not a weakly prime, because it can be changed into another prime (945001011139) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 472500505565 + 472500505566.

It is an arithmetic number, because the mean of its divisors is an integer number (472500505566).

Almost surely, 2^945001011131 is an apocalyptic number.

945001011131 is a deficient number, since it is larger than the sum of its proper divisors (1).

945001011131 is an equidigital number, since it uses as much as digits as its factorization.

945001011131 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 540, while the sum is 26.

The spelling of 945001011131 in words is "nine hundred forty-five billion, one million, eleven thousand, one hundred thirty-one".