Base | Representation |
---|---|
bin | 101100001010110011… |
… | …1111110100111100011 |
3 | 100001211101221000112112 |
4 | 1120111213332213203 |
5 | 3023224113112042 |
6 | 111324025145535 |
7 | 6565344252434 |
oct | 1302547764743 |
9 | 301741830475 |
10 | 94852082147 |
11 | 37254589239 |
12 | 1647192b2ab |
13 | 8c381308c4 |
14 | 483b49748b |
15 | 2702315982 |
hex | 16159fe9e3 |
94852082147 has 2 divisors, whose sum is σ = 94852082148. Its totient is φ = 94852082146.
The previous prime is 94852082107. The next prime is 94852082177. The reversal of 94852082147 is 74128025849.
It is a strong prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-94852082147 is a prime.
It is a super-2 number, since 2×948520821472 (a number of 23 digits) contains 22 as substring.
It is a junction number, because it is equal to n+sod(n) for n = 94852082095 and 94852082104.
It is not a weakly prime, because it can be changed into another prime (94852082107) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 47426041073 + 47426041074.
It is an arithmetic number, because the mean of its divisors is an integer number (47426041074).
Almost surely, 294852082147 is an apocalyptic number.
94852082147 is a deficient number, since it is larger than the sum of its proper divisors (1).
94852082147 is an equidigital number, since it uses as much as digits as its factorization.
94852082147 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 1290240, while the sum is 50.
The spelling of 94852082147 in words is "ninety-four billion, eight hundred fifty-two million, eighty-two thousand, one hundred forty-seven".
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