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94942150003 is a prime number
BaseRepresentation
bin101100001101011111…
…1100011110101110011
3100002001200101221102001
41120122333203311303
53023420142300003
6111341003434431
76600516650101
oct1303277436563
9302050357361
1094942150003
11372a0406588
1216497b25a17
138c509a76ac
144849420c71
15270a1a761d
hex161afe3d73

94942150003 has 2 divisors, whose sum is σ = 94942150004. Its totient is φ = 94942150002.

The previous prime is 94942149977. The next prime is 94942150019. The reversal of 94942150003 is 30005124949.

It is a strong prime.

It is a cyclic number.

It is not a de Polignac number, because 94942150003 - 25 = 94942149971 is a prime.

It is not a weakly prime, because it can be changed into another prime (94942150033) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 47471075001 + 47471075002.

It is an arithmetic number, because the mean of its divisors is an integer number (47471075002).

Almost surely, 294942150003 is an apocalyptic number.

94942150003 is a deficient number, since it is larger than the sum of its proper divisors (1).

94942150003 is an equidigital number, since it uses as much as digits as its factorization.

94942150003 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 38880, while the sum is 37.

The spelling of 94942150003 in words is "ninety-four billion, nine hundred forty-two million, one hundred fifty thousand, three".