Base | Representation |
---|---|
bin | 101100001101011111… |
… | …1100011110101110011 |
3 | 100002001200101221102001 |
4 | 1120122333203311303 |
5 | 3023420142300003 |
6 | 111341003434431 |
7 | 6600516650101 |
oct | 1303277436563 |
9 | 302050357361 |
10 | 94942150003 |
11 | 372a0406588 |
12 | 16497b25a17 |
13 | 8c509a76ac |
14 | 4849420c71 |
15 | 270a1a761d |
hex | 161afe3d73 |
94942150003 has 2 divisors, whose sum is σ = 94942150004. Its totient is φ = 94942150002.
The previous prime is 94942149977. The next prime is 94942150019. The reversal of 94942150003 is 30005124949.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 94942150003 - 25 = 94942149971 is a prime.
It is not a weakly prime, because it can be changed into another prime (94942150033) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (23) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 47471075001 + 47471075002.
It is an arithmetic number, because the mean of its divisors is an integer number (47471075002).
Almost surely, 294942150003 is an apocalyptic number.
94942150003 is a deficient number, since it is larger than the sum of its proper divisors (1).
94942150003 is an equidigital number, since it uses as much as digits as its factorization.
94942150003 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 38880, while the sum is 37.
The spelling of 94942150003 in words is "ninety-four billion, nine hundred forty-two million, one hundred fifty thousand, three".
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