Search a number
-
+
951201220221211 is a prime number
BaseRepresentation
bin1101100001000111001100101…
…0110101110101100100011011
311121201220221121111202210111211
43120101303022311311210123
51444133440044334034321
613211011450312203551
7404233006653052561
oct33021631265654433
94551827544683454
10951201220221211
1125609a199060923
128a8252040995b7
1331a9ab7597389b
1412ac65558aba31
1574e7dd75590e1
hex3611ccad7591b

951201220221211 has 2 divisors, whose sum is σ = 951201220221212. Its totient is φ = 951201220221210.

The previous prime is 951201220221169. The next prime is 951201220221283. The reversal of 951201220221211 is 112122022102159.

It is a weak prime.

It is an emirp because it is prime and its reverse (112122022102159) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 951201220221211 - 217 = 951201220090139 is a prime.

It is a super-2 number, since 2×9512012202212112 (a number of 31 digits) contains 22 as substring.

It is not a weakly prime, because it can be changed into another prime (951291220221211) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 475600610110605 + 475600610110606.

It is an arithmetic number, because the mean of its divisors is an integer number (475600610110606).

Almost surely, 2951201220221211 is an apocalyptic number.

951201220221211 is a deficient number, since it is larger than the sum of its proper divisors (1).

951201220221211 is an equidigital number, since it uses as much as digits as its factorization.

951201220221211 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 2880, while the sum is 31.

The spelling of 951201220221211 in words is "nine hundred fifty-one trillion, two hundred one billion, two hundred twenty million, two hundred twenty-one thousand, two hundred eleven".